4-4x^2=-140

Solution for 4-4x^2=-140 equation:

4-4x^2=-140

We move all terms to the left:

4-4x^2-(-140)=0

We add all the numbers together, and all the variables

-4x^2+144=0

a = -4; b = 0; c = +144;
Δ = b2-4ac
Δ = 02-4·(-4)·144
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-4}=\frac{-48}{-8}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-4}=\frac{48}{-8}
=-6
$